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Aptitude Day 179

Answers of Day 178:  1.        23(13/14) kg. 2.         26 years. Problems on Average: 1. 5 years ago, the average age of the family of 3 members was 20 years. 2 children having been born (with age difference of 3 years), the present average age of the family is the same. The present age of the youngest child is: Solution:                    Sum = 20*3 = 60.                   Present sum of the age of 3 members = 60+5(3) = 75.                           The average remains the same after their birth too. Hence,                    Sum = 20*5 = 100.                    Let the present age of the youngest child be x and the age of the other child be x+3.                    x + (x+3) = 100-75                    2x = 25-3                    x = 11 years. 2. The arithmetic mean of the scores of a group of students in a test was 40. The brightest 30% of them secured a mean score of 90 and the dullest 10% a mean score of 35. The mean score of re

Vocabulary Day 178

Ecstatic Thesaurus: Adjective : blissful                    crazy, very happy, dreamy, enthusiastic, flying high, frenzied, mad, overjoyed, upbeat, cheerful... Antonyms : unhappy, sorrowful...  Example sentences: ·            I'm ecstatic about this adventure.  ·            There is nothing to be ecstatic with this.

Aptitude Day 178

Problems to solve:                1. The average weight of 70 students in a class is 25 kg. 5 of them whose average weight is 35 kg leave the class and the other 5 students whose average weight is 20 kg join the class. What’s the average weight of the class? 2. The average of 6 men is increased by 5 years when 2 of them whose ages are 10 years and 12 years are replaced by 2 new men. The average age of the 2 new men is: 

Vocabulary Day 177

Amputate Thesaurus: Verb : cut off a limb            remove, eliminate, separate, excise, truncate, lop... Example sentences: ·           The doctor amputated his right leg in order to save him. ·            It needs to be amputated. 

Aptitude Day 177

Answers of Day 176:  1.        20. 2.        4200. Problems on Average: 1. The average weight of 10 persons increases by 3 kg when a new person comes in place of one of them weighing 40 kg. What might be the weight of the new person? Solution:                 Increased sum = 3*10 = 30.                 Weight of the new person = 40+30 = 70 kg.                (Note: Since the average increases by 3kg, we’re adding 30 to 40) 2.The average weight of 3 men A, B and C is 50 kg. Another man D joins the group and the average now becomes 60 kg. If another man E, whose weight is 5 more than that of D, replaces A, then the average weight of B, C, D and E becomes 58 kg. The weight of A is: Solution:                  A+ B+ C = 50(3) = 150                  A+ B+ C+ D = 60(4) = 240                  B+ C+ D+ E = 58(4) = 232                  E = D+5                 (A+ B+ C+ D)- (A+ B+ C) = D = 240-150 = 90.                 E = 90+5 = 95.        

Vocabulary Day 176

Lavatory Thesaurus: Noun : restroom            bathroom, washroom, toilet, latrine, shower, WC... Example sentences: ·           That girl's lavatory . ·            You'll find the boy's lavatory at the left. 

Aptitude Day 176

Problems to solve: 1. The average of 10 students in a group is 9 years. When the teacher’s age is included in it, the average increases by one. What’s the teacher’s age in years? 2. The average monthly salary of 10 employees in an organisation is 2000. If the manager’s salary is added, then the average salary increases by 200. What’s the manager’s monthly salary?