Answers of Day 178: 1. 23(13/14) kg. 2. 26 years. Problems on Average: 1. 5 years ago, the average age of the family of 3 members was 20 years. 2 children having been born (with age difference of 3 years), the present average age of the family is the same. The present age of the youngest child is: Solution: Sum = 20*3 = 60. Present sum of the age of 3 members = 60+5(3) = 75. The average remains the same after their birth too. Hence, Sum = 20*5 = 100. Let the present age of the youngest child be x and the age of the other child be x+3. x + (x+3) = 100-75 2x = 25-3 x = 11 years. 2. The arithmetic mean of the scores of a group of students in a test was 40. The brightest 30% of them secured a mean score of 90 and the dullest 10% a mean score of 35. The mean score of re
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