2. 6(2/3).
Problems on Simple Interest:
1. A sum of money becomes 3/2 of itself in 5 years at a certain rate of simple interest. The rate per annum is:
Solution:
Let the sum be x.
S.I = 3x/2 – x = x/2
R = (x/2)*100/x*5
= 10%.
2. A lends 5000 to B and a certain sum to C at the same time at 10% p.a. simple interest. If after 2 years, A altogether receives 2500 as interest from B and C, then the sum lent to C is:
Solution:
Let the sum lend to C be x.
(5000*10*2)/100 + (x*10*2)/100 = 2500
1/5[5000+x] = 2500
5000+x = 12500
x = 7,500.
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