1. An amount of 1990 is divided among X, Y and Z such that their shares be reduced by 6, 3 and 1 respectively, the remainders shall be in the ratio of 5:3:2. Then Z’s ratio was:
Solution:
1990-(6+3+1) = 1980.
Total parts = 10.
Z’s share = (1980/10)* 2
= 396.
2. The ratio between 2 numbers is 3:7 and their L.C.M is 1890.The second
number is:
Solution:
The
numbers are 3x and 7x.
Their L.C.M is 21x.
21x
= 1890
x = 90.
The
second number is 7x = 7(90)
= 630.
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