Skip to main content

Aptitude Day 90


Ratio and Proportion:

1. An amount of 1990 is divided among X, Y and Z such that their shares be reduced by 6, 3 and 1 respectively, the remainders shall be in the ratio of  5:3:2. Then Z’s ratio was:

Solution:
                1990-(6+3+1) = 1980.
                Total parts = 10.

                Z’s share = (1980/10)* 2
                                = 396.

2. The ratio between 2 numbers  is 3:7 and their L.C.M is 1890.The second number is:

Solution:
               The numbers are 3x and 7x.
               Their L.C.M is 21x.

               21x = 1890
               x = 90.

           The second number is 7x = 7(90)
                                                         = 630.


Comments

Popular posts from this blog

Aptitude Day 59

Answers of Day 58:     1. 1/90.     2. 20 Problems to solve: 1. The product of two numbers is 33 and the sum of their squares is 130. Find their difference. 2. The sum of two numbers is 100 and their difference is 20. Find their product.

Vocabulary Day 55

Dilemma Thesaurus: Noun : problem            double bind, difficulty, crisis, embarrassment, mess, puzzle...  Antonyms :  solution...  Example sentences:                  That's a serious dilemma we should think about that.          He'll never share his dilemma with anyone. 

Aptitude Day 55

Problems On Numbers 1. The difference between the squares of two numbers is 28000 and the sum of their numbers is 400. Find the numbers. Solution:                 Let the 2 numbers be x and y.                 (x 2 -y 2 ) / (x+y) = 28000/400                 (x+y)(x-y) / (x+y) =  70                 x-y = 70 ------ Equation 1                 x+y = 400 ---- Equation 2                 By solving equations 1 and 2 we get,                 x = 235 and y = 165.                 The numbers are 235 and 165. 2. The sum of three consecutive numbers is 315. The middle number is: Solution:                 Let t...