Skip to main content

Aptitude Day 91


Ratio and Proportion:

1. An alloy is to contain copper and lead in the ratio 3:5. The required to be melted with 27 kg of copper is:

Solution:
               Let the required lead to be melted be x.
               3:5 :: 27:x
               3x = 5*27
               x = 45.  

2. 40 kg of an alloy X is mixed with 90 kg of alloy Y. If alloy X has zinc and tin in the ratio 2:3 and alloy Y has tin and lead in the ratio 4:5, then the amount of tin in the new alloy is :

Solution:
                Let the amount of tin in the new alloy be a.

                Amount of tin in X and Y:
                (40/5)*3 = 24. (In alloy X)
                (90/9)*5 = 50. (In alloy Y)

                a = 24+50
                   = 74.

Comments

Popular posts from this blog

Aptitude Day 59

Answers of Day 58:     1. 1/90.     2. 20 Problems to solve: 1. The product of two numbers is 33 and the sum of their squares is 130. Find their difference. 2. The sum of two numbers is 100 and their difference is 20. Find their product.

Vocabulary Day 55

Dilemma Thesaurus: Noun : problem            double bind, difficulty, crisis, embarrassment, mess, puzzle...  Antonyms :  solution...  Example sentences:                  That's a serious dilemma we should think about that.          He'll never share his dilemma with anyone. 

Aptitude Day 55

Problems On Numbers 1. The difference between the squares of two numbers is 28000 and the sum of their numbers is 400. Find the numbers. Solution:                 Let the 2 numbers be x and y.                 (x 2 -y 2 ) / (x+y) = 28000/400                 (x+y)(x-y) / (x+y) =  70                 x-y = 70 ------ Equation 1                 x+y = 400 ---- Equation 2                 By solving equations 1 and 2 we get,                 x = 235 and y = 165.                 The numbers are 235 and 165. 2. The sum of three consecutive numbers is 315. The middle number is: Solution:                 Let t...