Problems on Permutations and Combinations:
1. In how many ways can a team 5 be chosen from 7 players?
Solution:
The Required number of ways = 7C5
= 7C7-5 = 7C2
= 7*6/1*2
= 21.
2. In how many ways, a group of 6 members can be selected from 8 men and 6 ladies, consisting of 4 men and 2 ladies?
Solution:
The Required number of ways = 8C4 * 6C2
= (8*7*6*5/ 1*2*3*4) * (6*5/1*2)
= 1050.
1. In how many ways can a team 5 be chosen from 7 players?
Solution:
The Required number of ways = 7C5
= 7C7-5 = 7C2
= 7*6/1*2
= 21.
2. In how many ways, a group of 6 members can be selected from 8 men and 6 ladies, consisting of 4 men and 2 ladies?
Solution:
The Required number of ways = 8C4 * 6C2
= (8*7*6*5/ 1*2*3*4) * (6*5/1*2)
= 1050.
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