2. 500.
Problems on Compound Interest:
1. The compound interest on 62,500 at 4% p.a. is 5100. The period is:
Solution:
Amount = 62,500 + 5100 = 67,600.
67600 = 62500(1 + 4/100)n
67600/62500 = (26/25)n
(26/25)2 = (26/25)n
n = 2 years.
2. There is a 60% increase in an amount in 6 years at simple interest. What will be the compound interest of 12,000 after 3 years at the same rate?
Solution:
Let P = 100.
R = 100*60/ 100*6
= 10%.
C.I = 12000 [(1 + 10/100)3 -1]
= 3972.
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