Skip to main content

Aptitude Day 63


Problems on Numbers:

 1.The numerator and the denominator of a fraction are in the ratio of 3:5. If 3 is added to the numerator, the result of the fraction that has a value 9/5 of the orginal fraction. Find the denominator of the fraction.

 Solution:
                Let the numerator and the denominator be 3x and 5x respectively.
                (3x+3) / 5x = 9/5 (3x/5x)
                (3x+3) = 9/5 (3x)
                5(3x+3) = 18x
                15x+15 = 18x
                3x = 15
                x = 5.
                The denominator is 5x = 25.

 2. When the numerator of the fraction increases by 9, the fraction increases by 3/11. Find its denominator.

 Solution:
               Let the numerator and the denominator be x and y respectively.
               x+9 / y = x/y + 3/11
               x+9-x / y = 3/11
               9/y = 3/11
               y = 33.
              The denominator is 33.



Comments

Post a Comment

Popular posts from this blog

Aptitude Day 16

Answers of Day 1 :   1. 10609                                    2. 99900025                                    3. 9409                                    4. 1010025                                      Problems On Ages              Today, in this topic, we're gonna see only the 3 models. Let's check it out. Problems: 1. John's age after 15 years will be 5 times his age 5 years back. What's the present age of John?   Solution: Let John's current age be x.                            ...
Post a Comment
Read more

Aptitude Day 10

      Answers of Day 9:       1. 6                                      2. 5                                      3. 0                                      4. 0                                      5. 6 The Cycle of Unit Digit:    Today we're gonna look at the cycle of unit digit  7.       7 1  =  7      7 2  = 4 9      7 3  = 34 3      7 4  = 240 1      7 5  = 1680 7      7 6  = 11764 9   ...
Post a Comment
Read more