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Aptitude Day 63


Problems on Numbers:

 1.The numerator and the denominator of a fraction are in the ratio of 3:5. If 3 is added to the numerator, the result of the fraction that has a value 9/5 of the orginal fraction. Find the denominator of the fraction.

 Solution:
                Let the numerator and the denominator be 3x and 5x respectively.
                (3x+3) / 5x = 9/5 (3x/5x)
                (3x+3) = 9/5 (3x)
                5(3x+3) = 18x
                15x+15 = 18x
                3x = 15
                x = 5.
                The denominator is 5x = 25.

 2. When the numerator of the fraction increases by 9, the fraction increases by 3/11. Find its denominator.

 Solution:
               Let the numerator and the denominator be x and y respectively.
               x+9 / y = x/y + 3/11
               x+9-x / y = 3/11
               9/y = 3/11
               y = 33.
              The denominator is 33.



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