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Aptitude Day 64


Problems on Numbers:

 1. 40 is divided into two parts such that the sum of 5 times the first and 20 times the second is 350. The smaller part is:
Solution:
              Let the 2 parts be x and y,
              x+y = 40    ---------- Equation 1
              5x+20y = 350 ------ Equation 2
              By solving equations 1 and 2, we get
              x = 30 and y = 10.
              The smaller part is 10. 

2. The sum of 4 numbers is 81. If 2 is subtracted from the first number, 2 is added to the second number, the third number is divided by 2 and the fourth number is multiplied by 2, then all the results are equal. What’s the largest number?

Solution:
                Let the 4 numbers be A,B,C and D.
                A-2 = B+2 = C/2 = 2D = X
                A= X+2, B = X-2, C = 2X, D = X/2
                X+2+X-2+2X+X/2 = 81
                4X+X/2 = 81
                9X/2 = 81
                X = 18.
                A=20, B= 16, C= 36, D= 9.

               The largest one is 36.

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