1. The sum of the number and its reciprocal is 122/11. What's the square value of that number?
Solution:
Let the number be x.
x+(1/x) = 122/11
x2+11-122x=0
(x-11)(11x-1)=0
x=11.
The square value of that number is 121.
(x-5)(x+11)=0
x=5.
The positive number is 5.
Comments
Post a Comment