1. Find the number which when multiplied by 4 is increased by 39.
Solution:
Let the number be x.
4x= x+39
3x=39
x=13
The required number is 13.
2. If a number, when divided by 3, is reduced by 12. Find the number.
Solution:
Let the number be x.
x/3 = x-12
x = 3x-36
2x=36
x=18
The number is 18.
3. The third part of a number is decreased by 8 which is equal to the sixth part of the number increased by 2. Find the number.
Solution:
Let the number be x.
(x/3)-8 = (x/6)+2
(x/3)-(x/6) = 10
(2x-x)/6 = 10
x/6 =10
x = 60
The number is 60.
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