Try to solve this problem [ Based on yesterday's model. If you have'nt checked out, check this out Aptitude Day 19]
Six years ago, the ratio of the ages of A and B was 6:5. Four years hence, the ratio of their ages will be 11:10. What’s B’s age at present?
Again, today we’re gonna see the problems regarding Problems On Ages.
1. The total ages of A, B and C is 93 years. Ten years ago, the ratio of their ages was 2:3:4. What’s the present age of C?
Solution:
Let the ages of A, B and C be 2x, 3x and 4x respectively.
Their total is 93.
Their present ages will be (2x+10), (3x+10) and (4x+10) respectively.
(2x+10)+(3x+10)+(4x+10) = 93
9x+30 = 93
9x = 63
x = 7
Present age of C is (4x+10) = 28+10 = 38 years.
2. The ratio of the present ages of 2 sisters is 1:2 and 5 years back, the ratio was 1:3. What will be the ratio of ages after 5 years?
Solution:
Let the present ages of two sisters be x and 2x respectively.
5 years back, their ages will be (x-5) and (2x-5) respectively and their ratio was 1:3.
Therefore,
(x-5)/(2x-5) = 1/3
3(x-5) = (2x-5)
3x-15 = 2x-5
x = 10
The ratio of their ages after 5 years is (x+5) : (2x+5) which is 15:25
On further simplification, we get 3:5
3. A is 40 years old and B is 60 years old. How many years ago was the ratio of their age
3: 5?
3: 5?
Solution:
(40-x)/(60-x) = 3/5
5(40-x) = 3(60-x)
200-5x = 180-3x
20 = 2x
x = 10
10 years ago, the ratio of their ages was 3:5.
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