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Aptitude Day 16


Answers of Day 1:   1. 10609
                                   2. 99900025
                                   3. 9409
                                   4. 1010025
                                   
Problems On Ages
             Today, in this topic, we're gonna see only the 3 models. Let's check it out.


Problems:

1. John's age after 15 years will be 5 times his age 5 years back. What's the present age of John? 
Solution: Let John's current age be x.                  
               So, after 15 years will be x+15.                 
               Before 5 years will be x-5.                              
               x+15= 5(x-5)                
               x+15=5x-25                    
               40=4x                    
                x=10. 
 Hence, his present age is 10 years.


2. The ages of 2 persons differ by 16 years. If 6 years ago, the elder one is 3 times as old as the young one, find their present ages.

Solution:  Let the age of the younger person be x. 
                Then the age of the elder ones = x+16.  
                3(x-6)=(x+16-6)  
                3x-18=x+10 
                x=14.
The younger person is 14 years old.
The elder one is x+16=14+16=30 years old.

3. The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.

Solution: Let the son's present age be x.
                Father's present age= 3x+3
                3x+3+3=  2(x+3)+10
                3x+6= 2x+16
                x=10.
                The present age of father is 3x+3 = 3(10)+3 = 33 years old.

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