Problem On Ages:
1. The ratio between the present ages of A and B is 5:3. The ratio between the A's age 4 years ago and B's age 4 years hence is 1:1. What's the ratio between the A's age 4 years hence and B's age 4 years ago ?
Solution:
The present ages of A and B is 5x and 3x respectively.
A's age (4 years ago) = 5x-4
B's age (4 years hence) = 3x+4
Hence,
(5x-4)/(3x+4) = 1/1
(5x-4) = (3x+4)
2x = 8
x = 4
The ratio between the A's age 4 years hence and B's age 4 years ago is
(5x+4):(3x-4)
(20+4):(12-4)
24:8
3:1
2. A is two years older than B who is twice as C. If the total of the ages A, B and C be 27, then how old is B ?
Solution:
Let C's age be x.
Then B's age will be 2x and
A's age will be 2x+2.
Their sum is 27 which is (2x+2)+2x+x = 27
5x+2 = 27
5x = 25
x = 5
B's age is 2x = 2(5) = 10 years.
3. A man is 24 years older than his son. In two years, his age will be twice the age of his son. What's the present age of father ?
Solution:
Let the son's age be x.
Then the father's age be x+24.
After 2 years, his age will be twice of his son,
x+24+2 = 2(x+2)
x+26 = 2x+4
x = 22
The present age of father is x +24 = 22+24 = 46 years.
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