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Aptitude Day 26

Problems on ages
1.  One year ago, A was four times as old as B. Six years hence, A's age will exceed B's age by 9 years. What's the ratio of the present ages of A and B?

 Solution:
                One year ago, let B's age be x and A's age is 4x.
                After 6 years, A's age will be 4x+1+6 and B's age will be x+1+6.
                As per the given, this becomes
                               (4x+1+6)-(x+1+6)=9
                                       4x+7-x-7=9
                                             3x=9
                                             x = 3
               The ratio of their present ages is            (4x+1):(x+1)
             13:4

2. Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what's the sum of the ages of R and Q and their difference?

Solution:
                R-Q=R-T  (Q is as much younger than R as he is older than T)
                R+T =R+Q = 50 (Given: R+T = 50)
                R-Q = Can't be determined.
             
                

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