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Aptitude Day 7

     
Answers of Day 6: 1. 4
                                2. 4
                                3. 8
                                4. 4

The Cycle of Unit Digit:
  
Today we're gonna look at the cycle of unit digit 3.

     33
     3= 9
     3= 27
     34 = 81
     3= 243
     3= 729
     37 = 2187
     38 = 6561   
     39 = 19683
     310 = 59049


If you notice the unit digit in all 10, you can see, it repeats. 3,9,7,1 (which I’ve highlighted) then again 3,9,7,1 and so on. 

So the cycle of unit digit 3 is

   3= 3 (if you get the remainder as 1)
   3= 9 (if you get the remainder as 2)
   3= 7 (if you get the remainder as 3)
   3= 1 (if you get the remainder as 0)

Example: Unit digit of the product of   33 * 3* 3=?

Solution:  Power/ 4. Since it has only 4 (3,9,7,1 ) in the cycle and it again repeats...

Power/4= 3/4. You will get the remainder 3 so the unit digit is 7
                6/4. The remainder will be 2 so the unit digit is 9
                9/4. The remainder will be 1 so the unit digit is 3

 7*9= 633*3=9. So the unit digit of this product is 9.


Problems to solve

1.    384*325 *376 *3=?

2.    363 * 3*367 *312 * 319 =? 

3.    327 * 333 * 379 =?

4.    311 * 315 * 390 =?


Answers are here Aptitude Day 8


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