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Aptitude Day 7

     
Answers of Day 6: 1. 4
                                2. 4
                                3. 8
                                4. 4

The Cycle of Unit Digit:
  
Today we're gonna look at the cycle of unit digit 3.

     33
     3= 9
     3= 27
     34 = 81
     3= 243
     3= 729
     37 = 2187
     38 = 6561   
     39 = 19683
     310 = 59049


If you notice the unit digit in all 10, you can see, it repeats. 3,9,7,1 (which Iā€™ve highlighted) then again 3,9,7,1 and so on. 

So the cycle of unit digit 3 is

   3= 3 (if you get the remainder as 1)
   3= 9 (if you get the remainder as 2)
   3= 7 (if you get the remainder as 3)
   3= 1 (if you get the remainder as 0)

Example: Unit digit of the product of   33 * 3* 3=?

Solution:  Power/ 4. Since it has only 4 (3,9,7,1 ) in the cycle and it again repeats...

Power/4= 3/4. You will get the remainder 3 so the unit digit is 7
                6/4. The remainder will be 2 so the unit digit is 9
                9/4. The remainder will be 1 so the unit digit is 3

 7*9= 633*3=9. So the unit digit of this product is 9.


Problems to solve

1.    384*325 *376 *3=?

2.    363 * 3*367 *312 * 319 =? 

3.    327 * 333 * 379 =?

4.    311 * 315 * 390 =?


Answers are here Aptitude Day 8


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