Problem On Ages:
1. The sum of present ages of a mother and her son is 60 years. Six years ago, mother's age was 5 times the age of the son. After 6 years, son's age will be:
Solution:
Let the present ages of son and mother be x and (60-x) respectively.
Six years ago,
(60-x)-6 = 5(x-6)
54-x = 5x-30
6x = 84
x = 14
After 6 years son's age will be x+6 = 14+6 = 20 years.
2. The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A?
Solution:
(A+B) - (B+C) = 12
A+B-B-C = 12
A-C = 12.
C is 12 years younger than A.
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