Skip to main content

Aptitude Day 25


Problem On Ages:

1. The sum of present ages of a mother and her son is 60 years. Six years ago, mother's age was 5 times the age of the son. After 6 years, son's age will be:

Solution:
                Let the present ages of son and mother be x and (60-x) respectively.
                Six years ago,
                                  (60-x)-6 = 5(x-6)
                                    54-x = 5x-30
                                       6x = 84   
                                         x = 14
                After 6 years son's age will be x+6 = 14+6 = 20 years.

2. The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A?

Solution:
                (A+B) - (B+C) = 12
                     A+B-B-C = 12
                          A-C = 12.
                C is 12 years younger than A.




                                   
                                          

Comments

Popular posts from this blog

Vocabulary Day 21

Stammer Thesaurus: Verb : stutter in speech, speak haltingly, speech defect           halt, hesitate, pause, stop, sputter... Antonyms : say quickly, pronounce, enunciate... Example sentences: ·          He was stammering when the teacher caught him red-handed. ·          One should avoid the stammering while delivering a speech. 

Aptitude Day 16

Answers of Day 1 :   1. 10609                                    2. 99900025                                    3. 9409                                    4. 1010025                                      Problems On Ages              Today, in this topic, we're gonna see only the 3 models. Let's check it out. Problems: 1. John's age after 15 years will be 5 times his age 5 years back. What's the present age of John?   Solution: Let John's current age be x.                            ...