Skip to main content

Aptitude Day 18

Problems On Ages

 1. The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what'll be the ratio of the ages of P and Q after 4 years?

Solution:
         Let the resent ages of P and Q is 6x and 7x respectively.
         If Q is 4 years old than P, then the equation will be 
                7x-6x=4
                     x=4

         The ratio of the ages of P and Q after 4 years will be 6x+4: 7x+4
        By substituting x value, the above equation becomes 28:32
        On further simplification, it becomes 7:8. This will be your answer.

2. At present, the ratio between the ages of P and Q is 4:3. After 6 years, P's age will be 26 years. What's the age of Q at present?  

Solution:
        Let the present ages of both will be 4x and 3x respectively.
       After 6 years, P's age will be 26 years so the equation will be
              4x+6=26 
                   x=5
        The age of Q = 3x=3(5)
                              = 15 years.

3. Present ages of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. What's X's present age in years?

Solution:
       Let the present ages of both will be 5x and 6x respectively.
       After 7 years, their ratio will be 6:7 where 6=5x+7 and 7=6x+7. So this becomes
               5x+7/6x+7 = 6/7
               7(5x+7) = 6(6x+7)
                35x+49 = 36x+42
                          x = 7
      X's present is 5x=5(7)
                                = 35 years.
       



Comments

Post a Comment

Popular posts from this blog

Aptitude Day 59

Answers of Day 58:     1. 1/90.     2. 20 Problems to solve: 1. The product of two numbers is 33 and the sum of their squares is 130. Find their difference. 2. The sum of two numbers is 100 and their difference is 20. Find their product.
Post a Comment
Read more

Vocabulary Day 55

Dilemma Thesaurus: Noun : problem            double bind, difficulty, crisis, embarrassment, mess, puzzle...  Antonyms :  solution...  Example sentences:                  That's a serious dilemma we should think about that.          He'll never share his dilemma with anyone. 
Post a Comment
Read more

Aptitude Day 55

Problems On Numbers 1. The difference between the squares of two numbers is 28000 and the sum of their numbers is 400. Find the numbers. Solution:                 Let the 2 numbers be x and y.                 (x 2 -y 2 ) / (x+y) = 28000/400                 (x+y)(x-y) / (x+y) =  70                 x-y = 70 ------ Equation 1                 x+y = 400 ---- Equation 2                 By solving equations 1 and 2 we get,                 x = 235 and y = 165.                 The numbers are 235 and 165. 2. The sum of three consecutive numbers is 315. The middle number is: Solution:                 Let t...
Post a Comment
Read more