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Aptitude Day 148

Problem on Probability:

A man and his wife appear in an interview for 2 vacancies in the same post. The probability of husband’s selection is 1/6 and the probability of wife’s selection is ¼. What’s the probability that only one of them is selected?

Solution:
                P(A) =1/6.
                P(A̅) = 1-1/6 = 5/6.

                P(B)=1/4.
                P(B̅)= 1-1/4 =3/4
              
               Since only one of them is selected, the probability will be
               P(A)*P(B̅) + P(A̅)+P(B) = 1/6 * 3/4 + 5/6 * 1/4
                                                       = 1/8 + 5/24
                                                       = 1/3.
             
                

Hey guys... From tomorrow we’re gonna see problems on Average. So stay tuned. 

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