Skip to main content

Aptitude Day 163

Problems on Average:

1. The average of 30 numbers is 20. If 2 numbers 10 and 50 are discarded, then the average of the remaining numbers is:

Solution:
                Sum of observations = 20*30 = 600.
                600-10-50 = 540.
               
                New average = 540/28 = 19.29.

2, The average of 10 numbers is 30. If one number is excluded, the average becomes 27. The excluded number is:

Solution:
                 Sum of observations = 30*10 = 300.

                After excluding the sum will be = 27*9 = 243.

                The excluded number = 300-243 = 57.


Comments

Popular posts from this blog

Vocabulary Day 60

Incur Thesaurus: Verb :  arouse            acquire, earn, gain, include, get, obtain...  Antonyms :  lose, exclude ...  Example sentences:         ·        He is incurred in that game. ·        She incurs a great knowlegde in science.        

Vocabulary Day 82

Flutter Thesaurus: Verb: wave rapidly            drift, agitate, dance, flicker, fluctuate, hover, oscillate, quiver, shake, vibrate...                                           Antonyms:  stay, remain, stay . ..  Example sentences:         ·        His heart flutters when he sees his crush.  ·       That incident causes a  flutter between them. 

Aptitude Day 5

Answers of Day 4 :   1. 9                                   2. 5                                   3. 9                                   4. 8 To find the unit digit in the product. This is similar to the last model where we will find the unit digit of the sum. Example: 432*459*28*48=? Solution:  2*9=18 , 8*8=64, 4*8= 32. The unit digit of the total product is 2.  Problems to solve Find the unit digit of the product in the following 1. 404*397*810*21 =? 2. 24*42*36*78 =? 3. 81*82*89 =? 4. 72*36*98*47 =? See you tomorrow friends... Check out the answers over here  Aptitude Day 6