Skip to main content

Aptitude Day 190

Problems on Simple Interest:

1. A sum fetched a total simple interest of 2700 at the rate of 3% p.a. in 6 years. What’s the sum?

Solution:
                   S.I = PTR/100

                   P = 100*2700/3*6
                      = 15000.

2. 1000 becomes 1200 in 4 years at a certain rate of simple interest. If the rate of interest is increased by 2%, what amount will 1000 become in 3 years?

Solution:
                 S.I = PTR/100

                 S.I = 1200-1000 = 200
                 R = 100*200/1000*4
                 R = 5%

                 New R = 5+2 = 7%

                 S.I = 1000*2*7/100
                 S.I = 140.


Comments

Post a Comment

Popular posts from this blog

Aptitude Day 47

Problem On Numbers 1. Three numbers are in the ratio 1:2:3 and their average is 180. What's the largest number? Solution:                 Let the numbers be x, 2x and 3x.                 x+2x+3x = 180                          6x = 180                            x = 30                The largest number is 3x = 90. Problem to solve: Three numbers are in the ratio of 4:2:3 and their product is 648. Find the smallest number. 
Post a Comment
Read more

Vocabulary Day 21

Stammer Thesaurus: Verb : stutter in speech, speak haltingly, speech defect           halt, hesitate, pause, stop, sputter... Antonyms : say quickly, pronounce, enunciate... Example sentences: ·          He was stammering when the teacher caught him red-handed. ·          One should avoid the stammering while delivering a speech. 
Post a Comment
Read more