Skip to main content

Aptitude Day 164

Problems on Average:

1. The average age of 20 students in a class is 12 years. The average age of 10 students is 11 years. What’s the average age of the remaining 10 students?

Solution:
                 1st sum = 12*20 = 240.
                 2nd sum = 11`*10 = 110.

                The average age of the remaining 15 students = (240-110)/10
                                                                                            = 130/ 10
                                                                                            = 13 years.


2. 15 children are too be divided into 2 groups A and B of 10 and 5 children. The average percentage marks obtained by the children of group A is 80 and the average percentage marks obtained by all the 15 children is 81. The average percentage marks obtained by the children of group B is:

Solution:
                1st Sum = 81*15 = 1215
                2nd Sum = 80*10 = 800.
 
               The average age of the remaining 5 students = (1215-800)/5
                                                                                       = 415/ 5

                                                                                       = 83. 

Comments

Popular posts from this blog

Vocabulary Day 21

Stammer Thesaurus: Verb : stutter in speech, speak haltingly, speech defect           halt, hesitate, pause, stop, sputter... Antonyms : say quickly, pronounce, enunciate... Example sentences: ·          He was stammering when the teacher caught him red-handed. ·          One should avoid the stammering while delivering a speech. 

Aptitude Day 16

Answers of Day 1 :   1. 10609                                    2. 99900025                                    3. 9409                                    4. 1010025                                      Problems On Ages              Today, in this topic, we're gonna see only the 3 models. Let's check it out. Problems: 1. John's age after 15 years will be 5 times his age 5 years back. What's the present age of John?   Solution: Let John's current age be x.                            ...