Problems on
average:
1. In James opinion,
his weight is greater than 45kg but less than 50kg. His brother doesn’t agree
with James and he thinks that his weight is greater than 40kg but less than
55kg. His mother’s view is that his weight cannot be greater than 48kg. If all
of them are correct in their estimation, what’s the average different probable
weights of James?
Solution:
Let James weight X kg.
Given conditions:
45 < X <50
40 < X <55
X < 48
46
and 47 are the values satisfied from the above conditions.
Average = Sum of
observations/ Number of observations
= (46+47)/2
= 93/2
= 46.5 kg.
2. The average of 10
numbers is zero. Of them, at the most, how many may be greater than zero?
Solution:
Average = 0.
Average = Sum of
observations/ Number of observations
0 = Sum of observations
/20
Hence, Sum of observations will be 0.
It’s quite possible that 9 of these numbers may be positive and if their
sum is x, then 10th number is –x.
So, at the most 9 numbers may
be greater than 0.
Comments
Post a Comment