Skip to main content

Aptitude Day 158

Problems on Average:

1. The sum of 3 consecutive odd numbers is 10 more than the average of these numbers. What’s the  1st of these numbers?

Solution:
                   [x+(x+2)+(x+4)] - [x+(x+2)+(x+4)]/ 3 = 10
                   (3x+6)-(3x+6)/3 = 10
                   (33x+6)(2/3) = 10
                   3x+6 = 15
                   x =3.

2, The average age of the boys in a class is 10 years and that of the girls is 9 years. The average age of the whole class is:

Solution:
                 In order to find the average, we’ve to know the number of boys and girls in the class. Since we don’t have either the number of girls and boys in the question, we couldn’t able to find the average age. The data is inadequate.


Comments

Popular posts from this blog

Aptitude Day 47

Problem On Numbers 1. Three numbers are in the ratio 1:2:3 and their average is 180. What's the largest number? Solution:                 Let the numbers be x, 2x and 3x.                 x+2x+3x = 180                          6x = 180                            x = 30                The largest number is 3x = 90. Problem to solve: Three numbers are in the ratio of 4:2:3 and their product is 648. Find the smallest number. 

Vocabulary Day 21

Stammer Thesaurus: Verb : stutter in speech, speak haltingly, speech defect           halt, hesitate, pause, stop, sputter... Antonyms : say quickly, pronounce, enunciate... Example sentences: ·          He was stammering when the teacher caught him red-handed. ·          One should avoid the stammering while delivering a speech.