Problems on Average:
1. Of the 3 numbers, the 1st is half of the 2nd, the 2nd is 7 times of the 3rd one. The average of the numbers is 92. The 2nd smallest number is:
Solution:
Let the 3rd number be x.
[x+ 7x +7x/2]/ 3 = 92
[2x+14x+7x]/2 = 92*3
23x = 92*6
x = 24.
The numbers are x, 7x, 7x/2 = 24, 168 and 84.
The 2nd smallest number is 84.
2. Of the 5 numbers whose average is 120, the 1st is one-third of the sum of the last 4. The 1st number is:
Solution:
Let the 1st number be x.
Sum = 120*5 = 600.
x = 1/3(Sum of the last 4 numbers)
Sum of the last 4 numbers = 3x
(x +3x)/5 = 120
4x=120*5
x = 150.
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