2. 3 hours.
Problems on Pipes and cisterns:
1. Two pipes can fill a tank in 6 and 8 hours respectively and a waste pipe can empty 22 gallons per hour. All the 3 pipes working together can fill the tank in 5 hours. The capacity of the tank is:
Solution:
Part filled by (A+B+C) – Part filled by (A+B) in 1 hour = 1/5 – (1/6 + 1/8) = -11/120
Note: Negative sign indicates emptying.
Volume of 11/120 part = 22 gallons
Volume of the tank = 22*(120/11) = 240 gallons.
2. Two pipes A and B can fill the tank in 13(1/3) and 20 minutes respectively. Both pipes are opened. The tank will be filled in 10 minutes, if the pipe B is turned off after:
Solution:
Let B is turned off after x minutes.
x(3/40+ 1/20) +(10-x)3/40 = 1
x = 5 minutes.
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