Skip to main content

Aptitude Day 283

Problems on Trains 

Formulae:

  • Time taken by a train of length ‘l’ meters to pass a pole or standing man = Time taken by the train to cover that same ’l‘ meters.
  • Time taken by a train of length ‘l’ meters to pass a stationary object of length ‘a’ meters is the time taken by the train to cover ‘(l+ a)’ meters.
  • If 2 trains are moving in the same direction, their relative speed should be their sum and the time taken by the 2 trains to cross each other = Sum of their lengths/ Relative speed.
  • If they run in the opposite direction, their relative speed will be their difference and the time taken by the 2 trains to cross each other = Sum of their lengths/ Relative speed.
  • If 2 trains start at the same time from points A and B towards each other and after crossing they take a and b seconds in reaching B and A respectively, then 
                                          (A’s speed): (B’s speed) = (b)1/2 : (a)1/2   

Comments

Post a Comment

Popular posts from this blog

Vocabulary Day 21

Stammer Thesaurus: Verb : stutter in speech, speak haltingly, speech defect           halt, hesitate, pause, stop, sputter... Antonyms : say quickly, pronounce, enunciate... Example sentences: ·          He was stammering when the teacher caught him red-handed. ·          One should avoid the stammering while delivering a speech. 
Post a Comment
Read more

Aptitude Day 16

Answers of Day 1 :   1. 10609                                    2. 99900025                                    3. 9409                                    4. 1010025                                      Problems On Ages              Today, in this topic, we're gonna see only the 3 models. Let's check it out. Problems: 1. John's age after 15 years will be 5 times his age 5 years back. What's the present age of John?   Solution: Let John's current age be x.                            ...
Post a Comment
Read more