Skip to main content

Aptitude Day 279

Problems on Time and Distance: 

1. A walks around a circular field at the rate of 1 round per hour while B runs around it at the rate of 3 rounds per hour. They start in the same direction from the same point at 8.30 A.M. they shall 1st cross each other at:

Solution:
                 Since they move in the same direction along the circle, they’ll 1st meet each other when there is a difference of 1 round between the 2.

                  Relative speed = 3-1 
                                          = 2 rounds/ hour.

                  Time taken to complete 1 round at his speed = 1/2 hr 
                                                                                         = 30 minutes.

2. A thief steals a car at 4.30 PM and drives it at 80 km/hr. The theft is discovered at  5 PM and the owner sets off in another car at 90 km/hr. When will he overtake the thief?

Solution:
                  Consider, the thief is overtaken x hours after 4.30 PM.

                  Distance covered by thief in x hours = distance covered by the owner in (x-1/2) hours.

                  80x = 90(x-1/2)

                  By solving this, we get
                  x = 9/2
                     = 4.5 hours.

                  The thief is overtaken at 9 PM.


Comments

Post a Comment

Popular posts from this blog

Aptitude Day 59

Answers of Day 58:     1. 1/90.     2. 20 Problems to solve: 1. The product of two numbers is 33 and the sum of their squares is 130. Find their difference. 2. The sum of two numbers is 100 and their difference is 20. Find their product.
Post a Comment
Read more

Vocabulary Day 55

Dilemma Thesaurus: Noun : problem            double bind, difficulty, crisis, embarrassment, mess, puzzle...  Antonyms :  solution...  Example sentences:                  That's a serious dilemma we should think about that.          He'll never share his dilemma with anyone. 
Post a Comment
Read more

Aptitude Day 55

Problems On Numbers 1. The difference between the squares of two numbers is 28000 and the sum of their numbers is 400. Find the numbers. Solution:                 Let the 2 numbers be x and y.                 (x 2 -y 2 ) / (x+y) = 28000/400                 (x+y)(x-y) / (x+y) =  70                 x-y = 70 ------ Equation 1                 x+y = 400 ---- Equation 2                 By solving equations 1 and 2 we get,                 x = 235 and y = 165.                 The numbers are 235 and 165. 2. The sum of three consecutive numbers is 315. The middle number is: Solution:                 Let t...
Post a Comment
Read more