Problems on
Probability:
1. In a simultaneous
throw of 2 dice, what’s the probability of getting a total of 10?
Solution:
n(S) = 36
E
= {(4,6), (5,5), (6,4)}
P(E) =
n(E)/ n(S)
= 3/36
= 1/12.
2. What’s the
probability of getting a sum 5 from 2
throws of a dice?
Solution:
n(S) = 36
E
= {(1,4), (2,3), (3,2),(4,1)}
P(E) = n(E)/ n(S)
= 4/36
= 1/9.

Comments
Post a Comment