Problems on
Probability:
1. In a simultaneous
throw of 2 dice, what’s the probability of getting a doublet?
Solution:
n(S) = 36
E
= {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}
P(E) = n(E)/ n(S)
= 6/36
= 1/6.
2. In a simultaneous
throw of 2 dice, what’s the probability of getting a total of 6 or 7?
Solution:
n(S) = 36
E
= {(5,1), (4,2), (3,3), (2,4), (1,5), (6,1), (5,2), (4,3), (3,4), (2,5), (1,6)}
P(E) = n(E)/ n(S)
= 11/36.
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