1. A tank is filled by 3 pipes with uniform flow. The 1st 2 pipes operating simultaneously fill the tank in the same time during which the tank is filled by the 3rd pipe alone. The 2nd pipe fills the tank 50 minutes faster than the 1st pipe and 40 minutes slower than the 3rd one. The time required by the 1st pipe is:
Solution:
Let the time taken by pipe 1 be x.
1/x + 1/(x-50) = 1/(x-90)
By solving this, we get x = 150 minutes.
2. A tank is filled in 2 hours by 3 pipes A, B and C. The pipe C is thrice as fast as B and B is twice as fast as A. How much time will A alone take to fill the tank?
Solution:
Let the time taken by A be x.
1/x + 2/x + 6/x = 1/2.
x = 18 hours.

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